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When a transparent medium of refractive index 1.5 and thickness of 2.5 xx 10^(-5) m is introduced in front of a slit in Young's experiment, how much shift of interference fringes will occur ? (d=0.4 mm and D=100 cm) |
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Answer» SOLUTION :Let displacement of interference fringe is `Deltax` Now `(Deltaxd)/(D)=t(mu-1)` path difference) `:. Deltax=(t(mu-1)D)/(d)` `:. Deltax=(2.5xx10^(-5)(1.5-1.0)xx1)/(5xx10^(-4))` `=2.5xx10^(-2)m-2.5` cm |
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