When a U^(238) nucleus originally at rest, decays by emitting an alpha particle having speed 'u' the recoiled speed of residual nucleus is:

When a U^(238) nucleus originally at rest, decays by emitting an alpha

1.	When a U^(238) nucleus originally at rest, decays by emitting an alpha particle having speed 'u' the recoiled speed of residual nucleus is:
Answer» `(-4U)/(238)` `(4u)/(238)` `(-4u)/(234)` `(4u)/(234)` Solution :The velocity of RECOIL is `UPSILON=-(m)/(M).u` `=-(4)/(234)xxu=(-4u)/(234)` Hence choice is (c).

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When a U^(238) nucleus originally at rest, decays by emitting an alpha particle having speed 'u' the recoiled speed of residual nucleus is:

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