1.

When a U^(238) nucleus originally at rest decays by emitting an alpha -particle having a speed 'u', the recoil speed of the residual nucleus is :

Answer»

`(-4u)/(234)`
`(4u)/(234)`
`(-4u)/(238)`
`(4u)/(238)`

SOLUTION :`m_(1)v+m_(2)u=0`
`234v+4u=0`
`v=(-4v)/(234)`
So recoil speed is `(4u)/(234)`


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