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When a wire loop is rotated in a magnetic field the direction of induced emf changes once in each .....

Answer»

`1/4` revolution
`1/2` revolution
1 revolution
2 revolution

Solution :`phi=NABomega SIN OMEGAT`
`THEREFORE (dphi)/(dt)=NABomega sin omegat`
In half revolution `omegat` becomes,
`omega(t+T/2)=omegat+(omegaT)/2`
`=omegat+(2pi)/T. T/2`
`=omegat+pi`


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