1.

When alphais the angle between plane of the coil and magnetic field vecB, flux linked with the coil is given byphi =____

Answer»

AB
`|VECAXXVECB|`
`AB cos alpha`
`vecA xx VECB`

SOLUTION :Here angle `THETA` is between `vecA` and `vecB=90^@-alpha`.
`therefore phi=vecA.vecB`
`=AB cos(90^@-alpha)`
`=AB sin alpha`
`therefore phi=|vecAxxvecB|`


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