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When ammonia is heated with cupric oxide, a molecule of ammonia willA. Gain 3 electrousB. Lose 3 electronsC. Gain 2 electronsD. Lose 2 electrons |
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Answer» Correct Answer - B `2NH_(3)+3CuO to N_(2)+H_(2)O +3Cu` `underset("( O.S.=-3)")(2NH_(3)) to underset("(O.S.=0)")(N_(2))` Thus each N atoms (or each `NH_(3)` molecule) loses 3 electrons |
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