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When an a.c. source is connected to an ideal inductor, show that the average power supplied by the source over a complete cycle is zero. |
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Answer» Solution :Let an alternating voltage `V = V_(m) sin omega t`is applied ACROSS an IDEAL inductor, then current in the CIRCUIT is given by `I = I_(m) sin (omega t -pi/2)` `therefore` Average POWER for one complex cycle of circuit will be `P_(av) = 1/T int_(0)^(T) V I dt = 1/T int_(0)^(T) V_(m) sin omegat, I_(m) sin (omega t -pi/2) dt =(V_(m)I_(m))/T int_(0)^(T) sin omegat(-cos omega t)dt` `(V_(m)I_(m))/(4 omega T) [1-1] =0` |
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