1.

When an arc of a circle of radius R subtends an angle of \(\frac {\pi }{4}\)at the center, and carries a current I, the magnetic field at the center is B = \(\frac {\mu_o I}{16R}\).(a) True(b) FalseThe question was posed to me in an interview for job.I would like to ask this question from Magnetic Field on the Axis of a Circular Current Loop topic in section Moving Charges and Magnetism of Physics – Class 12

Answer»

The correct option is (a) True

For explanation: Magnetic field at the CENTER of a circular arc of radius R, carries a current I and MAKES an angle θ at the center is GIVEN by

B = \(\FRAC {\mu_o I \theta}{4 \pi R}\)

In this case θ = \(\frac {\pi }{4}\)

B = \(\frac {\mu_o I (\frac {\pi }{4})}{4 \pi R}\)

B = \(\frac {\mu_o I}{16 R}\)



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