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When an electric current is passed through acidified water, `112ml` of `H_(2)` gas at `NTP` is collected at the cathode is `965` seconds. The current passed in amperes isA. 1B. 0.5C. 0.1D. 2 |
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Answer» Correct Answer - 2 `H_(2)O+e^(-)rarr(1)/(2)H_(2)+OH^(-)` mole of `H_(2)=(112)/(22400)=5xx10^(-3)` mole of `H_(2)=(E)/(F)It` `I=0.5` |
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