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| 1. |
When an electron jumps from 2nd stationary orbit to 1st stationary orbit of hydrogen atom, the emitted energy is______ ev. |
| Answer» SOLUTION : `10.2 EV [E_(2)- E_(1) = (-13.6)/((2)^(2)) -[-(13.6)/((1)^(2))] = +3.4eV]` | |