1.

When an electron jumps from the orbit n =2 to n= 4, then wavelength of the radiations absorbed will be (R is Rydberg's constant)

Answer»

`(16)/(3R)`
`(16)/(5R)`
`(5R)/(16)`
`(3R)/(16)`

Solution :WAVELENGTH `1/lambda=R [1/n_(1)^(2)-1/n_(2)^(2)]`
`1/lambda=R [1/((2)^(2))-(1)/((4)^(2))]`
`1/lambda=R [1/4-1/(16)]`
`1/lambda=R [(4-1)/(16)]`
`1/lambda=(3R)/(16)`
`lambda=(16)/(3R)`


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