When an ideal choke is connected to an ac source of 100V and 50Hz, a current of 8 A flows through the circuit, A current of 10 A flows throught the circuit when a pure resistor is connected instead of the choke coil. IF the two are connected in series with an ac supply of 100 V and 40 Hz, then the current in the circuit isA. `10A`B. `8A`C. `5sqrt2A`D. `10sqrt2A`

When an ideal choke is connected to an ac source of 100V and 50Hz, a c

1.	When an ideal choke is connected to an ac source of 100V and 50Hz, a current of 8 A flows through the circuit, A current of 10 A flows throught the circuit when a pure resistor is connected instead of the choke coil. IF the two are connected in series with an ac supply of 100 V and 40 Hz, then the current in the circuit isA. `10A`B. `8A`C. `5sqrt2A`D. `10sqrt2A`
Answer» Correct Answer - C `X_L=omegaL=100/8` `thereforeL=100/(8omega)=1/(8pi)``R=100/10=10Omega` Where R and L are connected in series, `Z=sqrt((1/(8pi)times2pitimes40)^2+10^2)=10sqrt2` `thereforeI=V/Z=100/(10sqrt2)=5sqrt2A`

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