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When an o-particle of mass m moving with velocity v bombards on a heavy nucleus of charge 'Ze', its distance of closest approach from the nucleus depends on m as |
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Answer» `(1)/(sqrt(m))` `(1)/(2)MV^(2)=(2Ze^(2))/(4pi epsi_(0)r_(0))` `:.r_(0)=(2Ze^(2))/(4pi epsi_(0)xx(1)/(2)mv^(2))` `:. In r_(0) prop (Ze^(2))/(pi epsi_(0)v^(2)m),(Ze^(2))/(pi epsi_(0)v^(2))` constant `:. r_(0) prop (1)/(m)` |
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