InterviewSolution
Saved Bookmarks
| 1. |
When an object is moved along the principle axis of a concave mirror placedin air, the image coincides with the object if the object is 50 cm from the mirror. If the mirror is placed at a depth of 20 cm in a transparent medium, the image coincides with the object when the object is 40 cm from the mirror. The refractive index of the liquid is |
|
Answer» `(5)/(4)` Since, it is given that, an object at 50 cm from pole is act like, it placed at 40 cm from the pole when mirror is placed inside a transparent medium. `rArr v_("real") = 50 cm` and `v_("apparent") = 40 cm` Now, distance outside the transparent medium, `D_("real") = v_("real")` - thickness of transparent medium, `D_("real") = 50 cm - 20 cm = 30 cm` Similarly, `D_("apparent") = (40 - 20) cm = 20 cm` Hence, the refractive index of the LIQUID, `mu = (D_("ACTUAL"))/(D_("apparent")) = (30)/(20) = (3)/(2)` `:.` Hence, the correct option is (C ). |
|