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When an object is placed normallyon the principal axis of a spherial mirror at a distance 'a' from its pole, its image is formed at a distance 'v' from the pole of mirror such that (1)/(v)+(1)/(u)=(1)/(f), where f = focal length of given mirror. The relation is called mirror formula and is true for all types of mirrors under all conditions. However, values of u, v and f must be put with proper signs are per the sign convention followed. If 'h' be the height of the linear object and h' the height of image, then ratio (h')/(h) is called linear magnification or lateral magnification and its value m is given as : m=(h')/(h)=-(v)/(u) What is the surface area of image of linear object formed by the given concave mirror? |
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Answer» SOLUTION :`because"Linear magnification m"=(h.)/(h)=-(v)/(u)` `therefore"Areal magnification "=(A.)/(A)=m^(2)=(v^(2))/(u^(2))` `rArr""A.=(v^(2))/(u^(2))xxA=((60)/(30))^(2)xx6cm^(2)=24cm^(2)` |
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