1.

When an object placed between the pole and focus of a concave mirror the image formed is ------

Answer»

a. real, INVERTED and SMALL
b. real, inverted and same size
c.Virtual, inverted and small
d. Virtual, erect and enlarged

Solution :d.For a concave mirror, f `lt 0 , u lt 0.`
For an object between pole and the focus, f `lt u lt ` 0
i.e., `(1)/(f) - (1)/(u) gt 0 "" i.e., (1)/(v) lt 0 `
Hence v is positive and lies to the right of the pole and so the image is virtual .
m = `(-v)/(u ) = (v)/(|u|) "since" (1)/(v) lt (1)/(|u|) , VGT |u|` . ,
Hence .m. is positive and`gt` 1. so the image is enlarged.


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