When applying miller’s theorem to resistors, resistance R1 is for node 1 and R2 for node 2. If R1>R2, then for same circuit, then for capacitance for which the theorem is applied, which will be larger, C1 or C2?(a) C1(b) C2(c) Both are equal(d) Insufficient dataThis question was posed to me in homework.Question is from Low Frequency Response and Miller Effect Capacitance in division Transistor Frequency Response of Analog Circuits

When applying miller’s theorem to resistors, resistance R1 is for no

1.	When applying miller’s theorem to resistors, resistance R1 is for node 1 and R2 for node 2. If R1>R2, then for same circuit, then for capacitance for which the theorem is applied, which will be larger, C1 or C2?(a) C1(b) C2(c) Both are equal(d) Insufficient dataThis question was posed to me in homework.Question is from Low Frequency Response and Miller Effect Capacitance in division Transistor Frequency Response of Analog Circuits
Answer» The correct OPTION is (a) C1 Easiest explanation: Given R1>R2 R/1-K > R/1-K^-1, and so 1-K^-1>1-K Thus K^2>1, K>1, K<-1 (correct) Thus, C1=C(1-K) and C2=C(1-K^-1) HENCE C1>C2.

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