1.

When calomel electrode acts as an anode then the reaction is

Answer»

`2 HG + 2 Cl^(-) to Hg_(2) Cl_(2) + 2e^(-)`
`Hg_(2) Cl_(2) to 2 Hg^(+) + Cl_(2) + 2e^(-)`
`Hg_(2) Cl_(2) + 2e ^(-) to 2 Hg + Cl_(2)`
`Hg_(2)Cl_(2) + 2e^(-) to 2 Hg + 2 Cl^(-)`

Solution :The cell REACTIONS are at ANODE (oxidation)
`2 Hg + 2 Cl^(-) to Hg_(2) Cl_(2) + 2 e^(-)`


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