1.

When CH_(2)=CH-COOH is reduced with LiAlH_(4), the compound obtained will be

Answer»

`CH_(3)-CH_(2)-CHO`
`CH_(3)-CH_(2)-COOH`
`CH_(2)=CH-CH_(2)OH`
`CH_(3)-CH_(2)-COOH`

Solution :`LiAlH_(4)` reduces only the -COOH WITHOUT reducig the DOUBLE BOND.
`CH_(2)=CH-COOH OVERSET(LiAlH_(4))to CH_(2)=CH-CH_(2)OH`.


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