1.

When Cl_(2) gas is passed through hot and conc. Solution of KOH, following compound is formed :

Answer»

KCl
`KClO_(3)`
`KClO_(2)`
`KClO_(4)`

Solution :`6KOH + 3Cl_(2) RARR 5KCl + KClO_(3) + 3H_(2)O`


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