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When Cu^(2+) ion is treated with KI,a white precipiate is formed. Explain the reaction with the help of chemical equation . |
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Answer» Solution :`i^(-)` ION is a strong REDUCING agent. It reduces `Cu^(2+)` to `Cu^(+)` `2Cu^(2+) + 4I^(-) RARR underset("(WHITE ppt.)")(Cu_(2)I_(2)) + I_(2)` |
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