1.

When electric current in a coil steadily changes from +2 A to -2 A is 0.05 s, an induced emf of 0.8 V is generated in it. Then the self Inductance of the coil is ....... H.

Answer»

0.2
0.4
0.8
0.1

Solution :`epsilon=-L (DI)/(dt)`
`therefore 8=(-L xx (-4))/0.05`
`therefore L=(8xx0.05)/4` = 0.1 H


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