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When electric current in a coil steadily changes from +2 A to -2 A is 0.05 s, an induced emf of 0.8 V is generated in it. Then the self Inductance of the coil is ....... H. |
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Answer» Solution :`epsilon=-L (DI)/(dt)` `therefore 8=(-L xx (-4))/0.05` `therefore L=(8xx0.05)/4` = 0.1 H |
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