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When electron with mass m is accelerated with volt V associated de-Broglie wavelength is lambda .When proton with mass M is accelerated with same voltage associated de-Broglie wavelength will be……… |
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Answer» <P>`LAMBDA((m)/(M))` `therefore lambda prop (1)/(sqrt(M))`[`because` Remaining TERMS are same] `therefore (lambda_(p))/(lambda_(e))=sqrt((m_(e))/(m_(p)))=sqrt((m)/(M))` `therefore lambda_(p)=lambda sqrt((m)/(M)) [because lambda_(e)=lambda]` |
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