1.

When excess of FeSO_(4) is added to sodium extract the compound formed "is" // "are"

Answer»

`Na_(2)[Fe(CN)_(6)]`
`Fe(OH)_(2)`
`Na_(2)SO_(4)`
`Na_(2)[Fe(SCN)]`

SOLUTION :`6NaCN + FeSO_(4) to Na_(4)[Fe(CN)_(6)] + Na_(2)SO_(4)`
`Na_(2)S + FeSO_(4) to Fes + Na_(2)SO_(4)`.


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