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When frequencies f_(1) and f_(2) are incident on two indentical photo sensitive surfaes ,maximum velocities of photo-electrons of mass m are v_(1) and v_(2) hence…… |
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Answer» `v_(1)^(2)-v_(2)^(2)=(2h)/(m)(f_(1)-f_(2))` `(1)/(2)mv_(max)^(2)=HF-phi` `therefore hf=(1)/(2)mv_(max)^(2)+phi` `therefore hf_(1)=(1)/(2)mv_(1)^(2)+phi [because v_(max)=v_(1)]` and `hf_(2)=(1)/(2)mv_(2)^(2)+phi[because v_(max)=v_(2)]` `therefore H(f_(1)-f_(2))=(1)/(2)m(v_(1)^(2)-v_(2)^(2))` `therefore (2h)/(m)(f_(1)-f_(2))=v_(1)^(2)therefore v_(1)^(2)-v_(2)^(2)=(2h)/(m)=(2h)/(m)(f_(1)-f_(2))` |
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