1.

When H_(2)O_(2) is added to an acidified solution of K_(2)Cr_(2)O_(7):

Answer»

Solution turns green due to FORMATION of `Cr_(2)O_(3)`
Solution turns yellow due to formation of `K_(2)CrO_(4)`
Solution gives green ppt of `Cr(OH)_(3)`

Solution :`Cr_(2)O_(7)^(2-)+2H^(+)+4H_(2)O_(2) to 2CrO(O_(2))_(2)("blue coloured")+5H_(2)O`.


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