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When `H_(2)S` is passed through `Hg_(2)^(2+)`, we get :A. `HgS`B. `HgS + Hg_(2)S`C. `HgS + Hg`D. `Hg_(2)S` |
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Answer» Correct Answer - C `Hg_(2)Cl_(2) + H_(2)S rarr 2HCl + underset((ppt))(HgS) + Hg` |
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