1.

When kinetic energy of proton is equal to energy of photon then ratio of de-Broglie wavelength of proton and photon is proportional to …..

Answer»

<P>E
`E^(-(1)/(2))`
`E^((1)/(2))`
`K_(2)=2K_(1)`

Solution :For photon `lambda_(p)=(hc)/€`
Where E is ENERGY of photon
For ptoyon `lambda_(p)=(h)/(sqrt(2mK))`
here m and K are MASS and kinetic energy of proton ,
`therefore (lambda_(p))/(lambda_(p))=(E )/(c )sqrt(2mK) propE^((1)/(2))[because E=K]`


Discussion

No Comment Found

Related InterviewSolutions