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When light is incident on a soap film of thickness 5xx10^(-5) cm, the wavelength of light reflected maximum in the visible region is 5320 Å. Refractive index of the film will be, |
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Answer» 1.22 `2murcosr=(2n+1)(LAMBDA)/(2) "" [thereforecosr=1]` `mu = ((2n + 1)lambda)/(4r)` For visible REGION, n = 2 `mu=((2(2)+1)xx5320xx10^(-10))/(4xx5000xx10^(-10))=0.5xx10^(-7)` `lambda = 500 Å` |
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