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When light of wavelength `300 nm` (nanometre) falls on a photoelectric emitter , however light of `600 nm` wavelength is sufficient for creating photoemission . What is the ratio of the work functions of the two emitters ?A. `1 : 2`B. `2 :1`C. `4 : 1`D. `1 : 4` |
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Answer» Correct Answer - B Work function ` = ( hc)/(lambda_(0))` , where `lambda_(0)` is threshold wavelength . `:. (W_(01))/(W_(02)) = (lambda_(02))/(lambda_(01)) = (2)/(1)` |
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