When light of wavelength λ is incident on a metal surface ,stopping potential is found to be V_circ . When light of wavelength nλ is in incident on the same metal surface ,stopping potential is found to be V_circ/(n+1). The threshold wavelength of the metal is

When light of wavelength λ is incident on a metal surface ,stopping p

1.	When light of wavelength λ is incident on a metal surface ,stopping potential is found to be V_circ . When light of wavelength nλ is in incident on the same metal surface ,stopping potential is found to be V_circ/(n+1). The threshold wavelength of the metal is
Answer» `n^3λ` `λ/n^2` `n^2λ` `(n+2)λ` ANSWER :D

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When light of wavelength λ is incident on a metal surface ,stopping potential is found to be V_circ . When light of wavelength nλ is in incident on the same metal surface ,stopping potential is found to be V_circ/(n+1). The threshold wavelength of the metal is

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