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When light rays are incident on a prism at an angle of `45^(@)`, the minimum deviation is obtained. If refractive index of the material of prism is `sqrt(2)`, then the angle of prism will beA. `30^(@)`B. `40^(@)`C. `50^(@)`D. `60^(@)` |
Answer» Correct Answer - D `(sin.(A+deltam)/(2))/(sin .(A)/(2))=mu, `But` (A+delta_(m))/(2)=i=45^(@)` So,` (sin 45^(@))/(sin(A//2))=sqrt(2)implies(1)/(2)=sin.(A)/(2)impliesA=60^(@)` |
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