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When monochromatic light of frequency f_(1) incident on photosensitive surface ,stopping potential obtained is V_(1).When same surface is incident with monochromatic light of frequency f_(2) is incident on same surface ,stopping potential will become...... |
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Answer» `V_(1)+(h)/(E )(f_(2)-f_(1))` `e(V_(2)-V_(1))=h(f_(2)-f_(1))` `therefore V_(2)-V_(1)=(h)/(e )(f_(2)-f_(1))` `therefore V_(2)=V_(1)+(h)/(e )+(h)/(e )(f_(2)-f_(1))` |
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