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When n, identical capacitors are connected in series then equivalent capacitance becomes x, and when the same are connected in parallel then equivalent capacitance becomes y. Calculate y/x. |
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Answer» Solution :`(1)/(C_(eq))=(1)/(C )+(1)/(C )+…`N times `RARR C_(eq)=(C )/(n)=x "" …(i)` Equivalent capacitanceof n identical CAPACITORS connected in PARALLEL is `C_(eq)=C+C+C….` n times `rArr C_(eq)=NC=y "" …(ii)` Dividing (ii) by (i), `(nC)/(C//n)=(y)/(x)` `rArr n^(2)=y//x` `or (y)/(x)=n^(2)` |
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