InterviewSolution
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InterviewSolution
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When `NH_(4)NO_(2)(s)` decomposes at373K , it forms `N_(2)(g)` and `H_(2)O(g)`. The `DeltaH` . For the reaction at one atmospheric pressure and 373 K is -223.6 kJ `mol^(-1)`of `NH_(4)NO_(2)(s)` decomposed. What is the value of `DeltaU` for the reaction under the same conditions ? ( Given `R = 8.31 J K^(-1) mol^(-1))` |
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Answer» Correct Answer - `-232. 9kJ mol^(-1)` `NH_(4)NO_(2)(s) rarr N_(2)(g) + 2H_(2)O(g) , Delta n_(g) = 3-0 =3` `DeltaU = DeltaH - Deltan_(g) RT = - 223.6 kJ mol^(-1) - ( 3 mol) xx ( 8.314 xx 10^(-3) k J K^(-1) mol^(-1)) xx ( 373K)` `= - 232 kJ mol^(-1)` |
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