When one computes the square root of the ratio of the permeability of free space to the permitivity of free space, one obtains sqrt(mu_(0)/epsilon_(0))=337. What is the unit of this quantity?

When one computes the square root of the ratio of the permeability of

1.	When one computes the square root of the ratio of the permeability of free space to the permitivity of free space, one obtains sqrt(mu_(0)/epsilon_(0))=337. What is the unit of this quantity?
Answer» farads joules volts ohms SOLUTION :Unit of `mu_(0)`= ohm sec/meter `C^(2) = 1/(mu_(0)epsilon_(0))` `RARR epsilon_(0) = 1/(C^(2) mu_(0))` C=velocity of light `xsqrt(mu_(0)/epsilon_(0)) = SQRT(mu_(0)^(2)C^(2))= mu_(0)C` Unit of C = metre/sec. Unit of `sqrt((mu_(0))/epsilon_(0)) =` unit of `mu_(0)C`= ohm sec/meter x meter/sec = Ohm.

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When one computes the square root of the ratio of the permeability of free space to the permitivity of free space, one obtains sqrt(mu_(0)/epsilon_(0))=337. What is the unit of this quantity?

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