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When one magnet is kept in 0.8 T magnetic field, magnetic force on each its two poles is 0.08 N. Then pole strength of each pole would be ......

Answer»

`10` Am
`0.1` Am
`0.1 Am^2`
`10 Am^2`

SOLUTION :`F= q_(m) B THEREFORE q_(m) = (F)/( B) = (0.08)/(0.8) = 0.1` Am


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