When one mole of CoCl_(3).5NH_(3)was treated with excess of silver nit – InterviewSolution

1.	When one mole of CoCl_(3).5NH_(3)was treated with excess of silver nitrate solution , 2 mol of AgCl was precipptated . The formula of the compound is :
Answer» `[Co(Nh_(3))_(5)Cl_(2)]Cl` `[Co(NH_(3))_(5)Cl]Cl_(2)` `[Co(NH_(3))_(4)Cl_(2)](NH_(3))Cl` `[Co(Nh_(3))_(3)](NH_(3))_(2)` Answer :B

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