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When photon of wavelength `lambda_(1)` are incident on an isolated shere supended by an insulated , the corresponding stopping potential is found to be `V`. When photon of wavelength `lambda_(2)` are used , the orresponding stopping potential was thrice the above value. If light of wavelength `lambda_(3)` is used , carculate the stopping potential for this case.A. `(hc)/(e) [(1)/(lambda_(3)) + (1)/(2 lambda_(2)) - (1)/(lambda_(1))]`B. `(hc)/(e) [(1)/(lambda_(3)) + (1)/(2 lambda_(2)) - (3)/(lambda_(1))]`C. `(hc)/(e) [(1)/(lambda_(3)) + (1)/( lambda_(2)) - (1)/(lambda_(1))]`D. `(hc)/(e) [(1)/(lambda_(3)) - (1)/( lambda_(2)) - (1)/(lambda_(1))]` |
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Answer» Correct Answer - B `K E_(lambda_1) = (hc)/(lambda_(1)) - psi = e Delta V` `K E_(lambda_2) = (hc)/(lambda_(2)) - psi = 2 e Delta V` `implies 3 ((hc)/(lambda_(1)) - psi) = (hc)/(lambda_(2)) -psi` `psi = hc ((3)/(2 lambda_(1)) - (1)/(2 lambda_(2)))` `implies K E_(lambda_3) = (hc)/(lambda_(3)) - hc [(3)/(2 lambda_(1)) - (1)/(2 lambda_(2))]` ` = hc [(1)/(lambda_(3)) + (1)/(2 lambda_(2)) - (3)/(2 lambda_(1))]` `e Delta V = hc [(1)/(lambda_(3)) + (1)/(2 lambda_(2)) - (3)/(2 lambda_(1))]` ` Delta V = (hc)/(e) [(1)/(lambda_(3)) + (1)/(2 lambda_(2)) - (3)/(lambda_(1))]` |
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