Saved Bookmarks
| 1. |
When σ=0, then what is the condition on ‘r’?(a) 0 |
|
Answer» RIGHT answer is (b) R=1 To EXPLAIN I would say: We know that z=e^sT Now substitute s=σ+jΩ and z=r.e^jω, that is REPRESENT ‘z’ in the polar form On EQUATING both sides, we get r=e^σT Thus when σ=0, the value of ‘r’ varies from r=1. |
|