1.

When σ=0, then what is the condition on ‘r’?(a) 0

Answer» RIGHT answer is (b) R=1

To EXPLAIN I would say: We know that z=e^sT

Now substitute s=σ+jΩ and z=r.e^jω, that is REPRESENT ‘z’ in the polar form

On EQUATING both sides, we get

r=e^σT

Thus when σ=0, the value of ‘r’ varies from r=1.


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