1.

When σ

Answer»

The correct choice is (a) 0
Explanation: We know that z=e^sT

Now SUBSTITUTE s=σ+jΩ and z=r.e^jω, that is represent ‘z’ in the polar form

On EQUATING both sides, we get

r=e^σT

Thus when σ<0, the value of ‘r’ VARIES from 0



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