1.

When shunt connected to galvanometer has the value equal to resistance of galvanometer, range of current meter would become _______

Answer»

twice
thrice
four times
five times

Solution :We have `S=G/(n-1)`
Here S = G
`thereforen-1=G/S=1""(becauseS=G)`
`thereforen=2`
Now, `I=nI_(G)=2I_(G)`


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