1.

When SO_(2) is passed through acidified K_(2)Cr_(2)O_(7) solution

Answer»

the solution TURNS blue
the solution is decolourised
`SO_2` is reduced
green `Cr_2(SO_4)_3` is formed.

Solution :`K_(2)Cr_(2)O_(7)+H_(2)SO_(4)+3SO_(2)rarr K_(2)SO_(4)+Cr_(2)(SO_(4))_(3)+H_(2)O`


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