When sulphur in the form of `S_(8)` is heated at `900 K`, the initial pressure of `1` atm falls by `10%` at equilibrium. This is because of conversion of some `S_(8)` to `S_(2)`. Find the value of equilibrium constant for this reaction.

When sulphur in the form of `S_(8)` is heated at `900 K`, the initial

1.	When sulphur in the form of `S_(8)` is heated at `900 K`, the initial pressure of `1` atm falls by `10%` at equilibrium. This is because of conversion of some `S_(8)` to `S_(2)`. Find the value of equilibrium constant for this reaction.
Answer» `S_(8)(g)hArr4S_(2)(g)` `{:(Initila "mole",,1,,0),(At equilibrium,,1-x,,4x),(,,(1-0.10),,(4xx0.10)),(,,=0.9,,=0.40):}` Applying the law of mass action, `K_(p)=([p_(S_(2))]^(4))/([p_(S_(8))])=((0.4)^(4))/0.9=0.0256/0.9~~0.03a`

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When sulphur in the form of `S_(8)` is heated at `900 K`, the initial pressure of `1` atm falls by `10%` at equilibrium. This is because of conversion of some `S_(8)` to `S_(2)`. Find the value of equilibrium constant for this reaction.

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