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When tertiary butyl alcohol and 1-butanol are separately treated with a few drops of KMnO_(4), in one case only the purple colour disappears and a brown precipitate is formed. Which of the two alcohols gives the above reaction and what is that brown precipitate. |
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Answer» Solution :1-butanol, being primary alcohol gets oxidised by dilute `KMnO_(4)`. The BROWN precipitate is DUE to the formation of manganese dioxide. `2KMNO_(4)+H_(2)Orarr 3KOH +underset("(brown precipitate)")underset("manganese dioxide")(2MnO_(2))+3(O)` `underset("1 - butanol")(CH_(3)-CH_(2)-CH_(2)-CH_(2)-OH)+overset(2(O))underset("room TEMP.")rarr underset("butanoic acid")(CH_(3)CH_(2)CH_(2)COOH)+H_(2)O` |
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