When the electric flux Phi_(e) in a region of space, of relative permittivity (dielectric constant) k = (epsi)/(epsi_(0)), varies with time it gives rise to a displacement current given by

When the electric flux Phi_(e) in a region of space, of relative permi

1.	When the electric flux Phi_(e) in a region of space, of relative permittivity (dielectric constant) k = (epsi)/(epsi_(0)), varies with time it gives rise to a displacement current given by
Answer» `EPSI(d Phi_(e))/(DT)` `(1)/(epsi)(dPhi_(e))/(dt)` `K(d Phi_(e))/(dt)` `(1)/(k)(d Phi_(e))/(dt)` ANSWER :A

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When the electric flux Phi_(e) in a region of space, of relative permittivity (dielectric constant) k = (epsi)/(epsi_(0)), varies with time it gives rise to a displacement current given by

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