1.

When the electromagnetic radiation of maximum wavelength of 2480 nm is incident on semiconductor. The band gap energy of semiconductor is ……eV. [6.6xx10^(-34)JS, C=3xx10^(8)m//s, 1eV=1.6xx10^(-19)J]

Answer»

0.9
0.7
0.5
1.1

Solution :0.5
`E_(g)=(hc)/(lambda)`
`E_(g)=(6.6xx10^(-34)xx3xx10^(8))/(248xx10^(-8)xx1.6xx10^(-19))`
`=(19.8xx10^(-26))/(396.8xx10^(-27))=0.049899xx10^(1)~~0.5eV`


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