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When the ninth term of an AP is divided by its second term we get 5 as the quotient, when the thirteenth term ia devided ny sixth term the quotient is 2 and the remainderis 5, then the seonnd term is |
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Answer» Let a be the first term ad d be the common difference, then`T_(9)=5T_(2)` `implies (a+8d)=5(a+d)` `:. 4a=3d" " "….(i)"` and `T_(13)=T_(6)xx2+5` `implies a+12d=2(a+5d)+5` `implies 2d=a+5" " "….(ii)"` From Eqs.(i) and (ii), we get `a=3` and `d=4` `:.T_(2)=a+d=7` |
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