1.

When the radius of a soap bubble is inreased from 1/sqrtpi in to 2/sqrtpicm, the work done is720 erg. Find the surface tension of the soap solution.

Answer»

SOLUTION :`w = 2 XX T [4piR_2^2 - 4piR_1^2]`
`720 = 2T[4pi xx 4/pi - 4pi xx 1/pi`]
`therefore 720 = 2T xx 12`
`thereforeT = 30` dyne/cm


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