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When the radius of a soap bubble is inreased from 1/sqrtpi in to 2/sqrtpicm, the work done is720 erg. Find the surface tension of the soap solution. |
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Answer» SOLUTION :`w = 2 XX T [4piR_2^2 - 4piR_1^2]` `720 = 2T[4pi xx 4/pi - 4pi xx 1/pi`] `therefore 720 = 2T xx 12` `thereforeT = 30` dyne/cm |
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