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When the same amount of zinc is treated separately with excess of `H_(2)SO_(4)` and excess of `NaOH`, the ratio of volumes of `H_(2)` evolved is:A. `1:1`B. `1:2`C. `2:1`D. `9:4` |
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Answer» Correct Answer - A `Zn+H_(2)SO_(4)rarrZnSO_(4)+H_(2)`, `Zn+2NaOHrarrNaZnO_(2)+H_(2)` |
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